Math, asked by mohammedfaizan258, 1 year ago

prove that sec²θ+ cosec²θ=sec²θ cosec²θ

Answers

Answered by HARSHITSHARMA14
4

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Answered by TheLifeRacer
8
HeY !!!

Here is ur solution ↔

Sec²¢ + Cosec²¢

We know that sec²¢ = 1/cos²¢
and cosec²¢ = 1/sin²¢

since, we can write

=> 1/cos²¢ + 1/sin²¢

=> sin²¢ + cos²¢ / sin²¢ cos²¢

but , sin²¢ + cos²¢ = 1

since, 1/sin²¢* cos²¢

= > cosec²¢ * sec²¢

LHS = RHS prooved ♻

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Hope it helps you !!!

@Rajukumar111
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