prove that sec²θ+ cosec²θ=sec²θ cosec²θ
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HARSHITSHARMA14:
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Answered by
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HeY !!!
Here is ur solution ↔
Sec²¢ + Cosec²¢
We know that sec²¢ = 1/cos²¢
and cosec²¢ = 1/sin²¢
since, we can write
=> 1/cos²¢ + 1/sin²¢
=> sin²¢ + cos²¢ / sin²¢ cos²¢
but , sin²¢ + cos²¢ = 1
since, 1/sin²¢* cos²¢
= > cosec²¢ * sec²¢
LHS = RHS prooved ♻
__________________________
Hope it helps you !!!
@Rajukumar111
Here is ur solution ↔
Sec²¢ + Cosec²¢
We know that sec²¢ = 1/cos²¢
and cosec²¢ = 1/sin²¢
since, we can write
=> 1/cos²¢ + 1/sin²¢
=> sin²¢ + cos²¢ / sin²¢ cos²¢
but , sin²¢ + cos²¢ = 1
since, 1/sin²¢* cos²¢
= > cosec²¢ * sec²¢
LHS = RHS prooved ♻
__________________________
Hope it helps you !!!
@Rajukumar111
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