Question

prove that: sec2 θ + tan2 θ = 5/3

Answer 1

Answer:

WKT (sec2x)^2-(tan2x)^2=1

LHS =

(sec2x+tan2x)(sec2x-tan2x)

this implies that sec2x-tan2x=3/5. ---(1)

we also know that sec2x+tan2x =5/3----(2)

subtract (2) from (1). and get the value of tan2x.