prove that sec² theta - cos² theta = tan² theta + sin² theta
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Answer:
sec²θ - cos²θ = tan²θ+ sin² θ
LHS = sec²θ - cos²θ
= tan²θ+1 - cos²θ [as sec²θ = tan²θ+1]
= tan²θ + sin²θ [ as sin²θ+cos²θ=1 , 1-cos²θ=sin²θ]
= RHS
hence proved
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