Question

prove that sec2 theta+cosec2 theta= sec2 theta cosec2 theta​

Answer 1

I HOPE IT WILL HELP YOU....

Answer 2

Step-by-step explanation:

$sec^{2}$∅ + $cosec^{2}$∅ = $sec^{2}$∅ . $cosec^{2}$∅

=> $\frac{1}{cos^{2}}$ Ф + $\frac{1}{sin^{2} }$ Ф --------( $sec^{2}$ Ф = $\frac{1}{cos^{2} }$ Ф, $cosec^{2}$ Ф = $\frac{1}{sin^{2} }$ Ф )

=> $\frac{sin^{2} + cos^{2} }{sin^{2}cos^{2} }$ -------( taking LCM )

=>  $\frac{1}{sin^{2}cos^{2} }$ ---------( $sin^{2}$ Ф + $cos^{2}$ Ф = 1 )

=>$sec^{2}$ Ф . $cosec^{2}$ Ф

∴ LHS=RHS

Hence, proved