prove that sec²A + cosec²A can never be less than 2
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1
As sec^2=1+tan^2. Cosec^2=1+cot^2
So when we addit become 2+tan^2 +cot^2
So when we addit become 2+tan^2 +cot^2
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5
sec²A + cosec²A = 1 + tan²A + 1 + cot²A= 2 + tan²A + cot²A
and there is also a value of tan sq. A and cot sq. A, therefore
sec²A + cosec²A can never be less than 2.
and there is also a value of tan sq. A and cot sq. A, therefore
sec²A + cosec²A can never be less than 2.
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