Question

prove that
sec²A-sin²A-2sin⁴A/2cos⁴A-cos²A=1​

Answer 1

Answer:

Sin²A+Cos²A=1

Step-by-step explanation:

=sec²A-ha{sin²A(cos2A)/cos²A(cos2A)}

{cos2A=(2cos²A-1)=(1-2sin²A)}

=sec²A-(sin²A/cos²A)

=sec²A-tan²A

=1+tan²A-tan²A

=1

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