Question

prove that √sec²O + cosec² O = tan O + cot O​

Answer 1

Answer :

tan O + Cot O

Explanation :

L.H.S =

=

$\sqrt{sec {}^{2} }0 \times + \sqrt{cosec {}^{2} }0 \\ = \sqrt{(1 + tan {}^{2} } 0 +) \sqrt{} (1 + cot {}^{2} 0) \\ = \sqrt{2 + tan {}^{2} } 0 + cot {}^{2} 0 \\ = \sqrt{tan {}^{2} } 0 + cot {}^{2} 0 + 2tan 0cot0 \\ = \sqrt{(tan0 + cot0) {}^{2} } \\ = tan0 + cot0 \\ = rhs$