Prove that sec²theta+cosec²theta can never be less than 2
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Answered by
3
Heya!!
Answer to your question:
❤sec^2 theta + cosec^2 theta
=1+ tan^2 theta + 1 + cot^2 theta
=2+tan^2theta +cot^2 theta>2 as squared term can never be negative.
Hope it helps ^_^
Answered by
0
sec square theta +cos square theta =sec square theta +cos square theta -2sec theta cos theta +2sec theta cos theta
=(sec theta - cos theta ) square + 2*1/cos theta * cos theta =(sec theta -cos theta )square+2>
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