Prove that √sec²theta+ cosec²theta= tan theta+ cot theta
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Step-by-step explanation:
√sec²A+cosec²A
=√1/cos²A+1/sin²A
=√sin²A+cos²A/sin²Acos²A
=√1/sin²Acos²A
=1/sinAcosA
=sin²A+cos²A/sinAcosA [sin²A+cos²A=1]
=sin²A/sinAcosA+cos²A/sinAcosA
=sinA/cosA+cosA/sinA
=tanA+cotA
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