Math, asked by wkdkfj2811, 1 year ago

Prove that √sec²theta+ cosec²theta= tan theta+ cot theta

Answers

Answered by sandy1816
4

Step-by-step explanation:

√sec²A+cosec²A

=√1/cos²A+1/sin²A

=√sin²A+cos²A/sin²Acos²A

=√1/sin²Acos²A

=1/sinAcosA

=sin²A+cos²A/sinAcosA [sin²A+cos²A=1]

=sin²A/sinAcosA+cos²A/sinAcosA

=sinA/cosA+cosA/sinA

=tanA+cotA

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