Prove that sec4Θ - sec2Θ = tan4Θ + tan2Θ?
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Answer:
LHS
sec4θ - sec2θ
= sec2 θ [ sec2 θ - 1 ] { taking sec2 θ as common }
= sec2θ . tan2θ
R.H.S.
tan4θ +tan2θ
= tan2θ [ tan2θ + 1 ]
= tan2θ . sec2θ
LHS = RHS
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