Question

prove that (sec4a - sec2a) = tan2a + tan4a

Answer 1

Answer:

Step-by-step explanation:

I assume that equation/formula is

sec^4 a - sec^2 a = tan^2 a + tan^4 a

(sec^2 a)(sec^2 a - 1) =

(sec^2 a)($\frac{1}{cos^2 \alpha }$ - 1) =

[ (sec^2 a = tan^2 a + 1) Pythagorean Identity]

(sec^2 a)(tan^2 a) =

(tan^2 a + 1)(tan^2 a) =

tan^4 a + tan^2 a