Question

Prove that (sec4theta- sec2 ) = tan4theta+
tan2thetha
with detail explanation only
what happens there​

Answer 1

Answer:

L.H.S.

sec4θ - sec2θ

= sec2 θ [ sec2 θ - 1 ]  { taking sec2 θ as common }

= sec2θ * tan2θ { * = multiply.}

R.H.S.

tan4θ +tan2θ

= tan2θ [ tan2θ + 1 ]

= tan2θ * sec2θ

or sec2θ * tan2θ

= > L.H.S. = R.H.S.

Answer 2

Answer:

your answer

Step-by-step explanation:

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