Math, asked by prithviraj3300, 1 year ago

Prove that sec6A-tan6A=3 tan2Asec2A +1

Answers

Answered by venkatlohith20141225
7

sec6A - tan6A = 3tan2Asec2A + 1

= sec6A = tan6A + 3tan2A sec2A +1

here is ur ans.

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Answered by lenovoideapadanishka
2

answer is in the attachment

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hope this helps you ^_^

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