Math, asked by chimu5881, 5 months ago

Prove that sec80- √3cosec80=4

Answers

Answered by friends73

0

Answer:

sec20o=4

Step-by-step explanation:

LHS :

3cosec20o−sec220o

=sin20o3−cos20o1

=sin20ocos20o3cos20o−sin20o

=sin20ocos20o2[23cos20o−21sin20o]

=sin20ocos20o2(sin60ocos20o−cos60osin20o)

=sin20ocos20o2sin(60o−20

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