Prove that sec80- √3cosec80=4
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Answer:
sec20o=4
Step-by-step explanation:
LHS :
3cosec20o−sec220o
=sin20o3−cos20o1
=sin20ocos20o3cos20o−sin20o
=sin20ocos20o2[23cos20o−21sin20o]
=sin20ocos20o2(sin60ocos20o−cos60osin20o)
=sin20ocos20o2sin(60o−20
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