Prove that:
(sec8A - 1)/(sec4A - 1) = tan8A/tan2A
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Step-by-step explanation:
LHS- (sec8a-1)/(sec4A-1)
= (1+tan8A-1)/(1+tan4A-1)
= (tan8A) /(tan4A)
= tan8A/tan4A
RHS
proved.
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