Math, asked by ludirm295, 11 months ago

Prove that:
(sec8A - 1)/(sec4A - 1) = tan8A/tan2A

Answers

Answered by rajeshchourusiya0786

2

Step-by-step explanation:

LHS- (sec8a-1)/(sec4A-1)

= (1+tan8A-1)/(1+tan4A-1)

= (tan8A) /(tan4A)

= tan8A/tan4A

RHS

proved.

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