Math, asked by Anonymous, 1 year ago

prove that :- sec8A-1/sec4A-1=tan8A/Tan2A

Answers

Answered by krishna125
4
(1-cos8A÷1-cos4A)cos4A/cos8A
2sin4A* cos4A*sin4A/2sin2A*cos8A*sin2A
sin8A*2sin2Acos2A/cos8A*2sin2A*sin2A
tan8A*cot4A
tan8A/tan4A
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