Prove that: (sec8A-1)/(sec4A-1) = tan8A/tan2A
Answers
Answered by
2
(1-cos8A)cos4A/(1-cos4A)cos8A
=(2 sin^2 4A cos4A) /2sin^2 A*cos8A
=sin8A(2sin2A cos2A) /2sin^2 2A cos8A
=tan8A cot2A
=tan 8A/tan 2A
Similar questions