Question

prove that secA-1 / secA+1 = 1-cosA/1+cosA​

Answer 1

Answer: please see answer in the pic given below

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Step-by-step explanation:

Answer 2

Now,

L.H.S. = (secA - 1)/(secA + 1)

= (1/cosA - 1)/(1/cosA + 1), since secA = 1/cosA

= {(1 - cosA)/cosA}/{(1 + cosA)/cosA}

= (1 - cosA)/(1 + cosA)

= R.H.S. [Proved]

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