Question

prove that secA [1-sinA)
[secA+
tan A] =1​

Answer 1

Step-by-step explanation:

LHS = sec A [ 1 -sin A ] [ sec A + tan A ]

=> [sec A - sin A ( sec A)] [ sec A + tan A ]

=> so , ( sec A - tan A ) ( sec A + tan A )

=> sec²A - tan² A

=> 1

LHS = RHS

HENCE ,

PROVED

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