Math, asked by lakshmipotti79, 11 months ago

prove that secA(1-sinA)(secA+tanA)=1​

Answers

Answered by adityaverma55424
0

Answer:

Your question is wrong

Corrected question and answer is given in the picture

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Answered by leo2768
0

Step-by-step explanation:

Step1:- SecA=1/CosA

TanA=SinA/CosA

put SecA and TanA in left hand side equation and me get:-

=(1/CosA)(1-SinA)((1/CosA) +(SinA/CosA)

=(1/CosA)(1-SinA)((1+SinA)/CosA)

=(1/CosA)(((1)²-(SinA)²)/CosA)

=(1/CosA)((CosA)²/CosA)

=CosA²/CosA²=1

LHS=RHS

hence proved

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