prove that secA(1-sinA)(secA+tanA)=1
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Step-by-step explanation:
Step1:- SecA=1/CosA
TanA=SinA/CosA
put SecA and TanA in left hand side equation and me get:-
=(1/CosA)(1-SinA)((1/CosA) +(SinA/CosA)
=(1/CosA)(1-SinA)((1+SinA)/CosA)
=(1/CosA)(((1)²-(SinA)²)/CosA)
=(1/CosA)((CosA)²/CosA)
=CosA²/CosA²=1
LHS=RHS
hence proved
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