prove that
secA(1-sinA)(secA+TanA)=1
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LHS=
secA(1-secA)(secA+tanA)
=[1/cosA](1-sinA)[1/cosA+sin÷cosA]
=(1-sinA)(1+sinA)/cos^2A
=1-sin^2A/cos^2A
=>cos^2A/cos^2A[:•{1-sinA=cosA}]
=1 proved RHS
i hope its help u
secA(1-secA)(secA+tanA)
=[1/cosA](1-sinA)[1/cosA+sin÷cosA]
=(1-sinA)(1+sinA)/cos^2A
=1-sin^2A/cos^2A
=>cos^2A/cos^2A[:•{1-sinA=cosA}]
=1 proved RHS
i hope its help u
arbazhaider:
thanks
u r real expert
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