prove that secA(1-sinA)(SecA+TanA)=1
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Answer:
Let us start with LHS
= (secA-sinA×secA) (secA+tanA)
=(secA-tanA) (secA+tanA) { secA=1/cosA and sinA/cosA=tanA}
= (sec²A-tan²A) { (a+b) (a-b)=a²-b²}
=sec²A-tan²A
=1
RHS {using identity}
Hence proved.
Step-by-step explanation:
hope this helps
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