Question

prove that secA(1-sinA)(SecA+TanA)=1

Answer 1

Answer:

Let us start with LHS

= (secA-sinA×secA) (secA+tanA)

=(secA-tanA) (secA+tanA) { secA=1/cosA and sinA/cosA=tanA}

= (sec²A-tan²A) { (a+b) (a-b)=a²-b²}

=sec²A-tan²A

=1

RHS {using identity}

Hence proved.

Step-by-step explanation:

hope this helps