Prove that : secA (1-sinA) (secA+tanA)=1
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secA(1-sinA)(secA+tanA)
= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)
= (1/cos²A)(1-sinA)(1+sinA)
= (1/cos²A)(1-sin²A)
= (1/cos²A)(cos²A)
= 1
= RHS
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= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)
= (1/cos²A)(1-sinA)(1+sinA)
= (1/cos²A)(1-sin²A)
= (1/cos²A)(cos²A)
= 1
= RHS
hope it helps
mark as brainliest
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Question: Prove that : secA (1-sinA) (secA+tanA)=1
Using identity (Sec²∅-tan²∅)=1
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