Prove that ( secA-cos A) (Cot A+ tan A)=tan A secA
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Step-by-step explanation:
( sec A-cos A) (Cot A+ tan A)=tan A sec A,
L H S=(sec A-cos A) * (cot A+tan A) ,
=(1/cos A - cos A) * cos A/sin A + sin A/cos A) ,
=(1-cos^2 A)/cos A * (sin^2 A + cos^2 A ) / sin A cos A) ,
={(sin^2 A) /cos A}*(1/sin A cos A) ,
=sin A/cos^2 A = (sin A/cos A)*(1/cos A)=tan A*sec A=R H S.
Hope it helps you
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