prove that :
( secA - cosA ) ( cotA + TanA ) = SecATanA.
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Answer:
secA=1/cosA
so,( 1/cosA-cosA) =(1-cos²A) /cosA
sin²A/cosA. eq (1)
cotA=1/tanA
(sec²A) /tanA. eq(2)
by multiplying equation(1) and(2) we will get
(sin²A*sec²A) /(tanA*cosA)
(tan²A)/sinA
tanA=sinA/cosA
(sinA*sinA)/(cosA*cosA*sinA)
tanA/cosA=tanA*secA
therefore,proved
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