prove that (secA+cosA)(secA-cosA)=tan^3A+sin^2A
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LHS
= (secA + cosA)(secA - cosA)
= sec²A - cos²A
= sec²A - (1 - sin²A)
= sec²A - 1 + sin2A.
[sec²A = 1 + tan²A ⇒ sec²A - 1 = tan²A]
= tan²A + sin²A
= RHS
Hence Proved !!!!
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