Math, asked by adventurous98765, 5 months ago

prove that (secA-cosecA) (1+tanA+cotA)= tanASecA-cotAcosecA

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Answered by nandika32

1

Answer:

Please mark BRAINLIEST...

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Answered by ankit7349

1

(secA - cosecA)(1+tanA+cotA)

= secA + tanA.secA + cotA.secA - cosecA - cosecA.tanA - cosecA.cotA

= secA + sinA.sec^2A + cosecA - cosecA - secA - cosec^2A.cosA

= sinA/cos^2A - cosA/sin^2A

= (sinA/cosA)secA - (cosA/sinA)cosecA

= tanA.secA - cotA.cosecA ( RHS )

Hence proved ...

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