Prove that secA/ cotA+tanA = sinA
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Answer:LHS = SecA/(CotA+TanA)
= (1/CosA)÷{(cosA/sinA)+(sinA/cosA)}
=(1/cosA)÷{(cos^2A+Sin^2A)/sinAcosA}
=(1/cosA)*{sinAcosA/1}
= SinA
= RHS
Step-by-step explanation:
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