Question

prove that secA+tanA= 1/SecA-TanA

Answer 1

1/secA-tanA =secA+tanA
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Multiply both sides by secA-tanA to get:
1 = [sec^2(A)-tan^2(A)]
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1 = [1/cos^2 - sin^2/cos^2]
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1 = [1-sin^2]/cos^2
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1 = [cos^2/cos^2]
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1 = 1
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Cheers,
Stan H.

Answer 2

LHS = 1sec A + tan A=1sec A + tan A × sec A − tan Asec A − tan A=sec A − tan Asec2A − tan2A=sec A − tan A1=sec A + tan A=RHS