Prove that (secA-tanA) ^2=1-sinA/1+sinA
Answers
Answered by
0
these can not be proved as this is an axiom.
I hope you have understood
Answered by
1
Answer:
LHS =(secA-tanA) ^2
= (1/cosA-sinA/cosA)^2
= (1-sinA/cosA)^2
= (1-sinA)^2/cos^2A
=(1-sinA)^2/1-sin^2A
= 1-sinA/1+sinA
=RHS
Similar questions