Question

Prove
that,
(secA + tanA)/(cosecA+cotA) =(cosecA - cotA)/(secA - tanA)​

Answer 1

Answer:

if we cross multiply then we get

(secA)^2-(tanA)^2=(cosecA)^2-(cotA)^2

according to trigonometric identities both values are equal to 1 then lhs=rhs

hence proved that they are equal