prove that secA / tanA + cotA = sin A
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Answer:
LHS,
secA/tanA+cotA
1/cosA/sinA/cosA+cosA/sinA
1/cosA/sin^2A+cos^2A/sinAcosA
sinA/sin^2A+cos^2A
=>SINA= RHS
LHS=RHS
HENCE PROVED
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