prove that seco +tan o = coso apon 1-Sino
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Step-by-step explanation:
secA+tanA
=1+sinA/cosA
=(1+sinA)(1-sinA)/cosA(1-sinA)
=(1-sin²A)/cosA(1-sinA)
=cos²A/cosA(1-sinA)
=cosA/1-sinA
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