Prove that secø-tanø=cosø÷1+sinø
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Answer:
1/cosΦ-sinΦ/cosΦ
1-sinΦ/cosΦ
(1-sinΦ)(1+sinΦ)/cosΦ(1+sinΦ)
1-sin²Φ/cosΦ(1+sinΦ)
cos²Φ/cosΦ(1+sinΦ)
cosΦ/(1+sinΦ)
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