Question

prove that: secpower2theta+ cosecpower2theta = secpower2theta ×. cosec2 power2 theta​

Answer 1

$\large{\boxed{\red{\sf{sec²x+cosec²x=sec²x.cosec²x}}}}$

$\large{\boxed{\red{\sf{\frac{1}{cos²x}+\frac{1}{sin²x}=sec²x.cosec²x}}}}$

$\large{\boxed{\red{\sf{\frac{sin²x+cos²x}{sin²x.cos²x}=sec²x.cosec²x}}}}$

$\large{\boxed{\red{\sf{\frac{1}{sin²x.cos²x}=sec²x.cosec²x}}}}$

$\large{\boxed{\red{\sf{sec²x.cosec²x=sec²x.cosec²x}}}}$

${\large{\green{\sf{★ Hence \:proved}}}}$