Math, asked by advaith595, 11 months ago

prove that (secx secy+tanx tany)^2-(secxtany+tanxsecy)^2=1

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Answered by tanishkdp

6

Answer:

thus last step is 1*1*(-1)"(-1)=1 ( bcz sec^2 x= 1+tan^2 x)

Step-by-step explanation:

(LOOK AT THE CIRCLED MINUS SIGN)

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Answered by mahendrayaduvanshi30

8

Question:To prove:(secxsecy+tanxtany)^2-(secxtany+tanxsecy)^2=1

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