prove that see the question in the photo
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heya !!!
here is your answer!!!
given =>
1 / 2 + √ 3
on rationalize we get
1 / 2 + √ 3 * 2 - √ 3 / 2 - √ 3
=>. 2 - √ 3 / 1 --------------------(1)
second ,
2 / √ 5 - √ 3 * √ 5 +√ 3 / √5 +√3
=> √ 5 + √ 3 --------------(2 )
now ,
third
1 / 2 -√5 * 2 + √ 5 / 2 + √ 5
=> 2 + √ 5 / -1. --------------------------(3)
now ,
adding 1 , 2 ,and 3 we get
2 - √ 3 + √ 5 + √ 3 -2 -√ 5
=> 0
hence , proved
0 = 0
hope it helps you dear !!!
thanks !!!
have a pleasant day !!
☺☺
here is your answer!!!
given =>
1 / 2 + √ 3
on rationalize we get
1 / 2 + √ 3 * 2 - √ 3 / 2 - √ 3
=>. 2 - √ 3 / 1 --------------------(1)
second ,
2 / √ 5 - √ 3 * √ 5 +√ 3 / √5 +√3
=> √ 5 + √ 3 --------------(2 )
now ,
third
1 / 2 -√5 * 2 + √ 5 / 2 + √ 5
=> 2 + √ 5 / -1. --------------------------(3)
now ,
adding 1 , 2 ,and 3 we get
2 - √ 3 + √ 5 + √ 3 -2 -√ 5
=> 0
hence , proved
0 = 0
hope it helps you dear !!!
thanks !!!
have a pleasant day !!
☺☺
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