Question

prove that
sin (0-90°)
16) Prove that
Cos (0-360°
tan (90°-O) cosec(90°+0)
+
+
cot (180°+0)
+
=-1​

Answer 1

Answer:

cos (90° + θ) = – sin θ

sec (- θ) = sec θ

tan (180° – θ) = – tan θ

sec (360° – θ) = sec θ

sin (180° + θ) = – sin θ

cot (90° + θ) = – tan θ.