Question

prove that sin 0 cos (90° - 0) + sin (90° — O) cos 0 = 1​

Answer 1

Step-by-step explanation:

given that

let LHS=

sin 0cos (90--0)+sin (90--0)cos0

now using

$sin(90 - \alpha ) = cos \alpha \\ cos(90 - \alpha ) = sin \alpha$

therefore LHS =sin0sin0+cos0cos0

now using

$\sin(0 ) = 0 \\ \cos(0) = 1$

LHS=0*0+1*1

=1=RHS

Answer 2

Answer:

as lhs= Rhs the above statement is proved by the given explanation