prove that sin 0 degree=0.
Answers
Answered by
7
sin theta is perpendicular/base
in triangle with 0° angle there will always be a straight single line I.e. only base
if base is x
then
sin0°= 0/x
= 0
hence proved!!!!!
in triangle with 0° angle there will always be a straight single line I.e. only base
if base is x
then
sin0°= 0/x
= 0
hence proved!!!!!
Answered by
7
Just assume a right angle traingle, it must be having an acute angle, just try making that acute angle 0 by bringing hypotenuse towards base, finally hypotenuse will come over base and becomes equal to base which means now perpendicular has become 0
since angle now is 0 degree
cos 0=base/hyp=1/1=1 (since hyp=base)
sin 0= perp/ hyp=0/hyp=0
since angle now is 0 degree
cos 0=base/hyp=1/1=1 (since hyp=base)
sin 0= perp/ hyp=0/hyp=0
Similar questions