Question

prove that sin^-1(3/5)+ cos^-1 (5/√26)= tan^-1(19/17) <br />plz give Ans step by step explanation​...... plz it's urgent......​

Answer 1

Answer:

According to the Question

= \bf\huge\frac{cos^2A + tanA\:- 1}{sin^{2}A }

= \bf\huge\frac{cos^2A\:tan^2A\:-sin^2A\:-\:cos^2A}{sin^2A}

= \bf\huge\frac{tan^2A\: - \:sin^2A}{sin^{2}A }

= \bf\huge Sec^2\:A-1

= \bf\huge tan^2 A

LHS = RHS

Answer 2

Answer:

multiply the number by a number greater than it and add 1

hope you understood