prove that sin^-1(3/5)+ cos^-1 (5/√26)= tan^-1(19/17)
plz give Ans step by step explanation
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Sin-¹ (3/5) + Cos-¹(5/√26)
tan-¹(3/4) + tan-¹(1/5)
tan-¹ {(3/4) + (1/5) / (1 - 3/4 * 1/5)}
tan-¹ {(15 + 4)/20 / (1 - 3/20)}
tan-¹ {(19/20) / (17/20)}
tan-¹( 19/20 × 20/17)
tan-¹ (19/17)
I hope it will helpful for u
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