Question

prove that sin÷1-cos=cosec+cot​

Answer 1

Answer:

sin /1-cos=sin /1-cos ×1+cos /1+cos

sin (1+cos)/1-cos^

sin (1+cos /sin ^

1+cos/sin

1/sin +cos /sin

cosec +cot

Answer 2

Answer:

$\frac{ \sin( \alpha ) }{1 - \cos( \alpha ) } = cosec (\alpha ) + \cot( \alpha ) \\ l.h.s. = > \\ \frac{ \sin( \alpha ) }{ 1 - \cos( \alpha ) } \times \frac{1 + \cos( \alpha ) }{1 + \cos( \alpha ) } \\ \\ \\ \frac{sin( \alpha \times (1 + \cos( \alpha ) ) }{ {1}^{2} - { \cos( \alpha ) }^{2} } \\ \frac{ \sin( \alpha ) \times 1 + \cos( \alpha ) }{ { \sin( \alpha ) }^{2} } = > \frac{1}{ \sin( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \alpha ) } \\ \\ = > cosec (\alpha ) + \cot( \alpha )$

may be it's helpful to you ✴️✴️