Question

Prove that,
sinθ/1+cos θ+sinθ/1−cos θ = 2/sinθ


plz help
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Answer 1

Answer:

sinO/1 + cosO + sinO/1 - cosO = 2 / sinO

+ cosO - cosO ( cancel ❌ )

so , sinO/1 + sinO/1 ( LCM ) = 2/ sinO

:- 2 / sinO = 2 sinO

Hence , proved !!!

Answer 2

sinx/1+cosx +sinx/1-cosx

sinx(1/1+cosx +1/1-cosx)

sinx( 1-cosx+1+cosx/1-cossquare x)

sinx(2/sinsquarex)

2/sinx hence prove

SORRY FOR NOT TAKING THE THETA