Question

prove that sin 135° - cos120°/ sin 135° - cos120° = 3+ 2root2​

Answer 1

Answer:

(sin135 - cos120) / (sin135 + cos120) = 3 + 2 * v2

[sin (90 + 45) - cos(60 + 60)] / [(sin (90 + 45) + cos (60 + 60)]

(sin90cos45 + cos90sin45) - (cos60.cos60 - sin60.sin60) / (sin90cos45 + cos90sin45) + (cos60.cos60 - sin60.sin60)

cos45 - ( 3/4 - 1/4) / cos45 + ( 3/4 - 1/4)

(1 / v2 - 1 / 2) / ( 1 / v2 + 1 / 2)

[( v2 - 1) / 2 ] / [ ( v2 + 1) / 2 ]

( v2 - 1) / ( v2 + 1)

( v2 - 1) * ( v2 - 1) / ( v2 + 1) * ( v2 - 1)

2 - 2v2 + 1 / (2 - 1)

3 - 2v2

Step-by-step explanation:

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