prove that sin (180° - 0) = cos (90° - 0).
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Step-by-step explanation:
we have
sin(a-b)= sina cosb - cosa sinb
cos(a-b)=cosa cosb + sina sinb
sin(180-0)=sin180×cos0-cos180×sin0
= 0×1-(-1)×0
=0-0=0
cos (90-0)=cos90×cos0+sin90×sin0
=0×1+1×0
=0+0=0
hence proved
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