Question

prove that :-
Sin (180°-A) •sin (270-A) •cot (90°+A) \
cos (270°+A)•cos (90°+A) • tan (360° - A)=cot A​

Answer 1

Answer:

Step-by-step explanation:

L.H.S. = sin (180°- A) sin (270°- A) cot ( 90°+ A) / cos (270°+ A ) cos (90°+A) tan ( 360°-A)

= sin A ( - cos A ) (- tan A) / sec A ( - sin A ) ( - cot A )

= sin A cos A ( sin A / cos A ) / ( 1/ cos A ) sin A ( cos A / sin A )

= sin² A / 1

= sin² A

I hope this is correct.