Question

Prove that sin^2 32 +sin ^2 58- tan^2 45=0

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

sin²32°+sin²58°-tan²45°

=sin²32°+{sin(90°-32°)}²-tan²45°

=sin²32°+cos²32°-tan²45°

=1–1 =0. {As,sin²x+cos²x = 1}