Math, asked by shwetadeshpande, 4 months ago

prove that sin(2π-A)cos(π+A)tan(π/2-A) ÷ sin(π/2-A)cos(2π-A)sin(π-A) = cosec A​

Answers

Answered by ajathasatru80
0

Answer:

tan(π+A)tan(

2

+A)sin(2π−A)

cos(π−A)cot(

2

π

+A)cos(−A)

=

tanA×(−cotA)×(−sinA)

−cosA×(−tanA)×cosA

=

sinA

cos

2

cosA

sinA

using tanAcotA=1

=

cosAsinA

cos

2

AsinA

=cosA

Answered

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