prove that sin(2π-A)cos(π+A)tan(π/2-A) ÷ sin(π/2-A)cos(2π-A)sin(π-A) = cosec A
Answers
Answered by
0
Answer:
tan(π+A)tan(
2
3π
+A)sin(2π−A)
cos(π−A)cot(
2
π
+A)cos(−A)
=
tanA×(−cotA)×(−sinA)
−cosA×(−tanA)×cosA
=
sinA
cos
2
A×
cosA
sinA
using tanAcotA=1
=
cosAsinA
cos
2
AsinA
=cosA
Answered
Similar questions