Question

Prove that sin^2 θ- cos^2 θ= 2sin^2 θ -1​

Answer 1

Step-by-step explanation:

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Answer 2

$\sin {}^{2} θ - \cos {}^{2} θ = 2 { \sin }^{2} θ - 1$

$lhs = \sin {}^{2} θ - \cos {}^{2} θ$

$\sin {}^{2} θ + \cos {}^{2} θ = 1 \\ \cos {}^{2} θ = 1 - \sin {}^{2} θ$

$\sin {}^{2} θ - ( 1 - \sin {}^{2} θ)$

$\sin {}^{2} θ - 1 + \sin {}^{2} θ)$

$2\sin {}^{2} θ - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: hp$

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